x^2-8x-12=32

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Solution for x^2-8x-12=32 equation:



x^2-8x-12=32
We move all terms to the left:
x^2-8x-12-(32)=0
We add all the numbers together, and all the variables
x^2-8x-44=0
a = 1; b = -8; c = -44;
Δ = b2-4ac
Δ = -82-4·1·(-44)
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{15}}{2*1}=\frac{8-4\sqrt{15}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{15}}{2*1}=\frac{8+4\sqrt{15}}{2} $

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